Vector R has length 9.00 cm at 40.0°. Find its x- and y- components
I iamthor41 New member Joined Oct 21, 2010 Messages 4 Oct 21, 2010 #1 Vector R has length 9.00 cm at 40.0°. Find its x- and y- components
M masters Full Member Joined Mar 30, 2007 Messages 378 Oct 21, 2010 #2 iamthor41 said: Vector R has length 9.00 cm at 40.0°. Find its x- and y- components Click to expand... Hi iamthor41, \(\displaystyle \cos 40^{\circ}=\frac{x-\text{component}}{9}\) \(\displaystyle \sin40^{\circ}=\frac{y-\text{component}}{9}\)
iamthor41 said: Vector R has length 9.00 cm at 40.0°. Find its x- and y- components Click to expand... Hi iamthor41, \(\displaystyle \cos 40^{\circ}=\frac{x-\text{component}}{9}\) \(\displaystyle \sin40^{\circ}=\frac{y-\text{component}}{9}\)
I iamthor41 New member Joined Oct 21, 2010 Messages 4 Oct 21, 2010 #3 Do I not multiply the results from cos 40 and sin 40 by 9?
M masters Full Member Joined Mar 30, 2007 Messages 378 Oct 22, 2010 #4 iamthor41 said: Do I not multiply the results from cos 40 and sin 40 by 9? Click to expand... Yes, that would be correct.
iamthor41 said: Do I not multiply the results from cos 40 and sin 40 by 9? Click to expand... Yes, that would be correct.