1) If the equation were \(\displaystyle \sqrt{2}x+ 1= 0\), could you solve it?Solve for 0 ≤ x ≤ 360
1. √2sinx+1=0
2. sin²θ+sinθ=0
3. cos²θ=1-2sin²θ
The answers are as follows:
1. x=225,315
2. x=0,180,270,360
3. x= 0,180,360
How do i get these answers?
thanks
How do i get these answers?