trigonometry

[robtrex]

if ax/cosӨ + by/sinӨ = a² - b²
and axsinӨ/cos²Ө - bycosӨ/sin²Ө = 0
prove that (ax)^2/3+(by)^2/3 = (a² - b²)^2/3

 

[Deleted member 4993]

if ax/cosӨ + by/sinӨ = a² - b² ........................(1)
and axsinӨ/cos²Ө - bycosӨ/sin²Ө = 0......................................................(2)
prove that (ax)^2/3+(by)^2/3 = (a² - b²)^2/3

axsinӨ/cos²Ө - bycosӨ/sin²Ө = 0

ax = by cot³(x)

Now continue......

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