two problems, to simplify by hand...

[silverlining326]

1. 125^2/5

2. -8^5/3


i have a third, but i cant find it...i will post later if i find it =]

 

[tristatefabricatorsinc]

for one I believe it would be the fifth root of 125 to the 2nd power

for the second question it would be the third root of 8 which is 2 to the fifth power

 

[silverlining326]

but how do you do that? thats what i need the explaining on =]

 

[tristatefabricatorsinc]

for instance...

the 3rd root of 125 is 5, you take 5 * 5 * 5 and it = 125

the third root of 8 is 2 since 2 * 2 * 2 = 8

if you had 4^1/2 for example

the 2 in the fraction means the square root of 4 and the top number means to the first power

does this make sense?

 

[pka]

\(\displaystyle \L
\left( {125} \right)^{\frac{3}{5}} = \left( {5^3 } \right)^{\frac{3}{5}} = \left( {5^{\frac{6}{5}} } \right) = 5\left( {5^{\frac{1}{5}} } \right)\)

\(\displaystyle \L
\left( { - 8} \right)^{\frac{5}{3}} = \left( { - 2^3 } \right)^{\frac{5}{3}} = - 2^5 = - 32\)