Verifying Trig Identities

Again -- Throw us a bone. Please try SOMETHING.
Again -- If nothing else comes to mind, convert all to sines and cosines.

Note: If the only thing you EVER think of is converting to sines and cosines, something is very wrong. You may be in the wrong class.
 
You could start with the right side and use the half angle formula \(\displaystyle \frac{1+cos(x)}{2}=cos^{2}(\frac{x}{2})\)
 
okay, how would i lay that out then? would i try to convert the right side? as in:

4 +/- (? 1+cos (x/2) - 2) / (?2)
 
bobbyflay21 said:
okay, how would i lay that out then? would i try to convert the right side? as in:

4 +/- (? 1+cos (x/2) - 2) / (?2)
Click to expand...

I have no idea what you are trying to do - but it should be:

\(\displaystyle 4cos^2\left (\frac{x}{2}\right ) \ - \ 2 \ = \ 4\left (\frac{1 \ + \ cos(x)}{2}\right ) \ - \ 2\)

and continue....
 
bobbyflay21 said:
so how would i go about trying to verify that

csc x sin 2x = 4((1/cos x) /2)-2 <<<< Where did you get that from?

You need to review your algebra before trying these problems.
Click to expand...
 
that should be the quation you laid our for me with the 4 in the front. i cannot lay it out like that from my computer
 
i cannot lay it out like that from my computer
Click to expand...


Yes, you can. Just type the LaTex code in your post. To see how it was done it click on 'quote' in the upper right corner of the post.
 
bobbyflay21 said:
so how would i go about trying to verify that

RHS = 4((1+cos x) /2)-2
Click to expand...

You are being careless while typing - you need to read what you posted.

Nevertheless - simplify it - if something is multiplied by 4 and then divided by 2 - what is the net effect?
 
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