We use Snell’s Law to solve this problem.
\(\displaystyle n_1\sin \theta_1 = n_2\sin \theta_2\)
where \(\displaystyle n_1\) and \(\displaystyle n_2\) are the refractive indices for the two materials.
The Law looks simple but it needs a careful analysis. When we are finding the critical angle, one of the angles must be \(\displaystyle 90^{\circ}\). How to decide? Easy, in the critical angle case we know that light must travel from a more dense medium (higher refractive index) to a less dense medium. So, the material that has the higher refractive index has the critical angle while the other material has the \(\displaystyle 90^{\circ}\) angle.
Let us compare their refractive indices:
Water \(\displaystyle \rightarrow 1.33\)
Lucite \(\displaystyle \rightarrow 1.51\)
Then,
\(\displaystyle 1.51\sin \theta_1 = 1.33\sin 90^{\circ}\)
This gives:
\(\displaystyle \theta_1 = \sin^{-1}\frac{1.33}{1.51} = 61.7^{\circ}\)
As we said earlier in the critical angle case we know that light must travel from a more dense medium. Therefore, the light must start in lucite.