where to start from???please help

iamageek

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Dec 8, 2009
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a tire of a car has a radius of 5 feet. what is the rpm when the car is traveling at a speed of 145 feet per sec? thanx
i tried by finding the Circumference, then multiplying it with 145....didnt work though :?
 
Hello, iamageek!

A tire of a car has a radius of 5 feet.
What is the rpm when the car is traveling at a speed of 145 feet per sec?

i tried by finding the Circumference, then multiplying it with 145. . . . . no

\(\displaystyle \text{Since }\,C \:=\:2\pi r\text{, we have: }\:2\pi(5) \:=\:10\pi \text{ ft/rev}\)

\(\displaystyle \text{The tire is moving at }145\text{ ft/sec.}\)

\(\displaystyle \text{Hence: }\:\frac{145\text{ ft/sec}}{10\pi\text{ ft/rev}} \;=\;\frac{29}{5\pi}\text{ rev/sec}\)

\(\displaystyle \text{Therefore: }\:60 \times \frac{29}{5\pi}\text{ rev/sec} \;=\;\frac{860}{\pi}\text{ rev/min} \;\approx\; 277\text{ rpm.}\)

 
Yes it is!

145/(10pi) = 5(29)/{5(2pi)} = 29/(2pi) multiplied by 5/5

In one revolution of the tyre the car moves forward 5(2pi) feet assuming no skidding.
145 feet per second is 5(29) feet per second.
 
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