word problem about sin & cos

[alyren]

if friction is ignored, the time t(inseconds) required for a block to slide down an inclined plane by the formula
t=square root [ (2a)/(g*sin(data)*cos(data))]
where a is the length (in feet) of the base and g~32 feet per second per second is the acceleration due to gravity. How long does it take a block to slide down an inclined plane with base a=10 when data =30 degrees? around the answer to nearest tenth if necessary.

so far i got
t= sqrt[(20)/ (32*sin30degree*cos30degree)]
t= sqrt[(20)/(32*(1/2)*((sqrt3)/2)]
t= sqrt(1.4434)
t= 1.2 sec.

is this right?

 

[mmm4444bot]

I'm not familiar with the formula, but you properly evaluated the expression for t with the given values.

t = 1.2 is properly rounded, too.