equation

tiigrike

New member
Joined
Oct 30, 2011
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12
I have equation like this:
Q=((a-2b)±√(a^2+4ab+4b^2-8bc))/4b


How i get the solution? And what conditions i get , like b is not 0, but a and c?
 
I have equation like this:
Q=((a-2b)±√(a^2+4ab+4b^2-8bc))/4b


How i get the solution? And what conditions i get , like b is not 0, but a and c?

As posted, you can have b = 0 [ you posted Q=((a-2*b)±√(a^2+4*a*b+4*b^2-8*b*c))/4 * b]

you probably should have posted:


Q=((a-2*b)±√(a^2+4*a*b+4*b^2-8*b*c))/[4 * b]

Anyway, I am not sure what you do mean by "solution". Please expound.

Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
 
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