Need help with my geometry!!!!
- Thread starter NICK909
- Start date
HI,
I NEED HELP WITH MY GEOMETRY.
use the pythgorean theorem to find the distance between each pair of points
C(-10,2),D(-7,6) E(-2,-1),F(3,11)G(-2,-6),H(6,9)
You'll find everything you need right here:
http://www.purplemath.com/modules/distform.htm
HallsofIvy
Elite Member
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- Jan 27, 2012
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Do you not know what the Ptythagorean theorem is? If you don't then the first thing you should have done was look it up!HI,
I NEED HELP WITH MY GEOMETRY.
use the pythgorean theorem to find the distance between each pair of points
C(-10,2),D(-7,6) E(-2,-1),F(3,11)G(-2,-6),H(6,9)
To apply it, look at the first pair of points, C(-10, 2), and D(-7, 5). Draw the line segment between those two points. That's the length you want to find. Draw a line from (-10, 2) to (-7, 2), parallel to the x- axis. Its length is easy to find: it is |-10- (-7)|= |-3|= 3. Draw a line from (-7, 2) to (-7, 5), parallel to the y- axis. Its length is also easy to find: it is |5- 2|= |3|= 3. Do you see that those three lines form a right triangle with CD as hypotenuse? So you have a right triangle in which you know the lengths of the two legs and want to find the length of the hypotenuse- apply the Pythagorean theorem.
In case you were wondering, to get "each pair of points", you have to pair C with each of the other 5 points, D, E, F, G, and H. Because the "distance from C to D" is the same as the "distance from D to C" you don't have to do that again but you do have to pair D with each of the remaining 4 points. E, F, G, and H. And then pair E with the remaining three points, F, G, and H, F with G and H, and, finally, G with H. That is a total of 5+ 4+ 3+ 2+ 1= 15 distances to calculate. Get busy!