Fraction Trobule
- Thread starter lingping7
- Start date
D
Deleted member 4993
Guest
Hello everyone, I am stuck here with a problem
View attachment 2538
Since nobody will sit there subtracting all the terms and then multiplying them, I would like to know a method to these kind of questions.
Thanks in Advance
Hint:
Factorize 2 out - and continue.....
You need find the solution - what effort did you make?
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http://www.freemathhelp.com/forum/th...217#post322217
We can help - we only help after you have shown your work - or ask a specific question (not a statement like "Don't know any of these")
Please share your work with us indicating exactly where you are stuck - so that we may know where to begin to help you.
Where are the brackets??
Last edited by a moderator:
lillybeth
Junior Member
- Joined
- Nov 1, 2012
- Messages
- 211
the person who posted the question did show exactly where he/she was stuck. :?:
D
Deleted member 4993
Guest
Not really!! For the level of the problem, one should quickly realize that the 2 factors out. The OP should show(or state) that as first step as his/her work. In the absence of that, I give that "silly" hint and wait for more work (and lecture from the corner.....)
Hello, lingping7!
You finally gave us the parentheses . . .
If you had done the subtractions, you would get:
. . \(\displaystyle \left(\frac{5}{3}\right) \left(\frac{7}{5}\right) \left(\frac{9}{7}\right)\left(\frac{11}{9}\right) \cdots \left(\frac{999}{997}\right)\left(\frac{1001}{999}\right)\)
After reducing, you have: \(\displaystyle \dfrac{1001}{3}\)
You finally gave us the parentheses . . .
If you had done the subtractions, you would get:
. . \(\displaystyle \left(\frac{5}{3}\right) \left(\frac{7}{5}\right) \left(\frac{9}{7}\right)\left(\frac{11}{9}\right) \cdots \left(\frac{999}{997}\right)\left(\frac{1001}{999}\right)\)
After reducing, you have: \(\displaystyle \dfrac{1001}{3}\)