help! Trigo Graphs!

[kinuel8091]

y= 3 sin (13x/4 - pi/6)


First I have to get the Amplitude, Period and interval of y=3sin 13x/4 right?
A=3
P=8pi/13
I=2pi/13

Then get the coordinates

X	0	2pi/13	4pi/13	6pi/13	8pi/13
y	0	3	0	-3	0

Then graph? then shift to the right by pi/6
But then, i dont know how to shift it by pi/6

 

[HallsofIvy]

Add pi/6 to each x value, keep the same y value.

 

[kinuel8091]

like this?

Add pi/6 to each x value, keep the same y value.

x	pi/6	25pi/78	37pi/78	49pi/78	61pi/78
y	0	3	0	-3	0

Actually my real problem is how to insert does values in the graph

 

[Deleted member 4993]

x	pi/6	25pi/78	37pi/78	49pi/78	61pi/78
y	0	3	0	-3	0

Actually my real problem is how to insert does values in the graph

Those "x's will not let you proper graph.

Using those numbers you will get a saw-tooth graph.

I think what HoI meant for you to do is to evaluate the function at π/6 interval. So you will have 12 'x' values from 0 to 2π (e.g. 0, π/6, π/3, π/2,..)

x = 0 → (13x/4 - π/6) = -π/6 → y = -1.5

x = π/6 → (13π/24 - π/6) = 3π/8 → y = 2.7716

x = π/3 → (13π/12 - π/6) = 11π/12 → y = 0.7765

and so on....

 

[kinuel8091]

those "x's will not let you proper graph.

Using those numbers you will get a saw-tooth graph.

I think what hoi meant for you to do is to evaluate the function at π/6 interval. So you will have 12 'x' values from 0 to 2π (e.g. 0, π/6, π/3, π/2,..)

x = 0 → (13x/4 - π/6) = -π/6 → y = -1.5

x = π/6 → (13π/24 - π/6) = 3π/8 → y = 2.7716

x = π/3 → (13π/12 - π/6) = 11π/12 → y = 0.7765

and so on....

thank you! :d