The point P(-5,-6) divides the line joining A(7,6) and B(x,y) in the ratio 1:3. :o
J Jerome2013 New member Joined Jan 10, 2014 Messages 1 Jan 10, 2014 #1 The point P(-5,-6) divides the line joining A(7,6) and B(x,y) in the ratio 1:3.
pka Elite Member Joined Jan 29, 2005 Messages 11,990 Jan 10, 2014 #2 Jerome2013 said: The point P(-5,-6) divides the line joining A(7,6) and B(x,y) in the ratio 1:3. Click to expand... I will tell you how to do this. But keeping in line with forum policy will not do it. The line segment \(\displaystyle \overline{AB}=<t(x-7)+7,~t(y-6)+6>,~0\le t\le 1~.\) Note that \(\displaystyle A\) corresponds to \(\displaystyle t=0\) and \(\displaystyle B\) corresponds to \(\displaystyle t=1\). So \(\displaystyle P\) corresponds to \(\displaystyle t=\frac{1}{4}\). Now you can find \(\displaystyle (x,y)\).
Jerome2013 said: The point P(-5,-6) divides the line joining A(7,6) and B(x,y) in the ratio 1:3. Click to expand... I will tell you how to do this. But keeping in line with forum policy will not do it. The line segment \(\displaystyle \overline{AB}=<t(x-7)+7,~t(y-6)+6>,~0\le t\le 1~.\) Note that \(\displaystyle A\) corresponds to \(\displaystyle t=0\) and \(\displaystyle B\) corresponds to \(\displaystyle t=1\). So \(\displaystyle P\) corresponds to \(\displaystyle t=\frac{1}{4}\). Now you can find \(\displaystyle (x,y)\).