System of Coupled Higher Order Differential Equations

saheedimran

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May 13, 2014
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Hi all,
I am a PhD student in Structural Mechanics and I need some help/hints in solving a system of coupled higher order differential equations. The equations and the boundary conditions are specified in the attached zip file. Any useful information or suggestions on how to proceed with the solution will be highly appreciated.

Thanks.
 

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  • Coupled Differential Equations.zip
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The equations and the boundary conditions are specified in the attached zip file.
If you can't be bothered to type out your question, it's unlikely that anybody is going to be bothered to type out a response. In addition, nobody having any Internet-security savvy at all is going to touch a ZIP file of unknown origin. Sorry. ;)
 
System of Coupled Higher Order Differential Equation

Sorry, my bad.



I have the following equations with the aim of finding the following terms:

σ1, σ2, σ3, σ4, W1, W2, W3, U1, U2, U3

N1'-σ1=0

N2'+σ12=0

N3'+σ2=0

M1''+c1 σ1'-σ3=0

M2''+c2σ1'+c2σ2'+σ34=0

M3''+c3σ2'+σ4=0

v1=v2+K1σ1

v2=v3+K2σ2

w1=w2-K3σ3

w2=w3-K4σ4


ck (k=1,2,3) and Ki (i =1,2,3,4) are constant coeffcients.

N1'=D1U1''-E1σ1''+F1σ3'

N2'=D2U2''+E21''-σ2'')+F23'+σ4')

N3'=D3U3''+E3σ2''+F3σ4'

M1''=-A1W1''''+B1σ1'''-T1σ3''

M2''=-A2W2''''+B21'''+σ2''')+T23''-σ4'')

M3''=-A3W3''''+B3σ2''+T3σ4''


Additional equations
φ1+W1'=R1(Q1-m1σ1)

φ2+W2'=R2[Q2-m212)]

φ3+W3'=R3(Q3-m3σ2)

Q1'-σ3=0

Q2'+σ34=0

Q3'+σ4=0


Ak, Bk, Dk, Ek, Fk, Tk, Rk, mk (k=1,2,3) are constant coefficients.
All the primed letters denote differentiation with respect to x.

Boundary conditions

At x=0

Uk=0, φk=0, Qk=0 (k=1,2,3)

x=L

Mk=0, Nk=0, Qk=0
(k=1,2,3)
 
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