If sinx=1/5 and x is an acute angle, then sin(pi/3+x) is?

pwndogmaster1

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What is the answer to this question?
If sinx=1/5 and x is an acute angle, then sin(pi/3+x) is?
 
What is the answer to this question?
If sinx=1/5 and x is an acute angle, then sin(pi/3+x) is?



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Duplicate Post:

https://answers.yahoo.com/question/index?qid=20141201150612AAlU4YY&act=aq

Hints:

sin(x) = 1/5 → cos(x) = ?

sin(A+B) = sin(A) * cos(B) + cos(A) * sin(B) → sin(π/3 + x) = ?
 
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If sinx=1/5 and x is an acute angle, then sin(pi/3+x) is?
If x is acute, what is the largest value it could possibly have? So then in what quadrant(s) must (pi/3) + x lie? So then what must be the sign of the sine of (pi/3) + x? What is the angle-sum identity for sines? What did you get when you applied this information?

Please be complete. Thank you! ;)
 
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