Please help! How to past the θ to the left? Finally becomes θ = xxxxxxxx

[res578]

How to past the θ to the left? Finally becomes θ = xxxxxxxx

\(\displaystyle r\, =\, \left(\dfrac{-\left(f\, \cdot\, \sin(\theta)\right)\, -\, \sqrt{\left(f\, \cdot\, \sin(\theta)\right)^2\, +\, 2as\,}}{a}\right)\, \times\, \left(f\, \cdot\, \cos(\theta)\right)\)

 

[Deleted member 4993]

How to past the θ to the left? Finally becomes θ = xxxxxxxx

\(\displaystyle r\, =\, \left(\dfrac{-\left(f\, \cdot\, \sin(\theta)\right)\, -\, \sqrt{\left(f\, \cdot\, \sin(\theta)\right)^2\, +\, 2as\,}}{a}\right)\, \times\, \left(f\, \cdot\, \cos(\theta)\right)\)

Looks like you are working with the expression for the range of a projectile. Try squaring both sides and use trig identities to get a quadratic function for sin(x).

What are your thoughts?

Please share your work with us ...even if you know it is wrong

If you are stuck at the beginning tell us and we'll start with the definitions.

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