Find the solution of the given initial value problem in explicit form"
dy/dx=2x/(1-2y) , y(2)=0
So I seperated to (1-2y)dy=2xdx, which I then integrated to get y-y2=x+c. I then found c to be -4.
So I have y-y2=x-4 but I have no idea how to get down to only one y.
Any help is appreciated!
dy/dx=2x/(1-2y) , y(2)=0
So I seperated to (1-2y)dy=2xdx, which I then integrated to get y-y2=x+c. I then found c to be -4.
So I have y-y2=x-4 but I have no idea how to get down to only one y.
Any help is appreciated!
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