PDE: Solve Uyy+4U=cot(2y), given U=u(x,y)

[awesomesauce9596]

Hello everyone,

My questions states to solve Uyy+4U=cot(2y), given U=U(x,y).

So far I am able to get that my lambdas are plus and minus 2i. However, after that I'm not sure which direction to go because the cot(2y) throws me off. Thanks for all the help!

 

[Deleted member 4993]

Hello everyone,

My questions states to solve Uyy+4U=cot(2y), given U=U(x,y).

So far I am able to get that my lambdas are plus and minus 2i. However, after that I'm not sure which direction to go because the cot(2y) throws me off. Thanks for all the help!

What type of math course you are taking? Your posts indicate that you have questions about definitions, differentiations and then solution of PDE. Is this an On-line course without an instructor to guide you?

By the way, after solving for lambdas, what did you get for the homogeneous part of your PDE?

 

[awesomesauce9596]

What type of math course you are taking? Your posts indicate that you have questions about definitions, differentiations and then solution of PDE. Is this an On-line course without an instructor to guide you?

By the way, after solving for lambdas, what did you get for the homogeneous part of your PDE?

I'm out of school but am going to take a PDE course soon, I got some practice problems to work on for now so I can be up to speed when I return. I got that U_h= G(x)cos(2y)+ F(x)sin (2y).....if that's even right.

Now, by just looking at it, am I going to have to do variation of parameters because of the cot(2y)? I just feel way off on everything.