ShubhamRathi
New member
- Joined
- Aug 28, 2016
- Messages
- 1
Consider the Equations.:
g'(rd*)G = 1 ... (3)
[ Q it-1 (Qt/ Q t-1) + Δ qit* ] l (rcit*)=1 ... (4)
Just if someone wants to get in more details, the paper is here. This result is Lemma 2 on page 10/23.
g'(rd*)G = 1 ... (3)
[ Q it-1 (Qt/ Q t-1) + Δ qit* ] l (rcit*)=1 ... (4)
Its then said, Differentiating (3)-(4) with respect to Qit - 1 and rearranging yields:
** What is D. How does one calculate it? Can someone please explain the calculus that is happening here?**d rc*/d Q it-1 = g’’ (rdit) G m’’ (Δ qit) l’ (rcit*) x (Qt/ Q t-1) /D ... (5)
d Δ qit* / d Q t-1 = g’’ (rdit) G l’ (rcit )2 x (Qt/ Q t-1) /D ... (6)
where D is the determinant of the matrix of second partials.d Δ qit* / d Q t-1 = g’’ (rdit) G l’ (rcit )2 x (Qt/ Q t-1) /D ... (6)
Just if someone wants to get in more details, the paper is here. This result is Lemma 2 on page 10/23.