I not sure how to repost these problems in a different way. The first problem is of an isosceles triangle with a circle inscribed in it. The angle of 42 degrees is given. I need to find the value of the variables, which are the three arcs. I know that since one angle is 42 degrees, the other two are 69degrees each. I also know that the two arcs across the 69 degree angles are congruent. And, the formula for finding the arcs is
m<=1/2(arc 1- arc 2). I'm just not sure what to do since all of the arcs are variables.
In the second problem, two segments are meeting outside of the circle, and going through the circle. I need to find the value of x, given the other values of segment lengths. X and 4 are the segment lengths outside of the circle. 12 and 8 are the segment lengths inside of the circle. I know the formula is
z(12+z) = 4(4+8). That gives me
z^2 + 12z = 48. I can then do
z^2 + 12z -48 = 0
Now, I am stuck. I can't get This to factor, so I can't solve for z.
I appreciate any help you can give. Thank you!
