Inverse Trignometry: if x1,x2,x3,x4 are roots of eqn, then find sum of tan^-1 x

namitha

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If x1,x2,x3,x4 are the roots of the equation x4-x3


sin2(Beta)+x2 cos 2(Beta)-x cos(Beta)-sin(Beta)=0 then
summation i=1 to 4 of tan^-1 xi is ?
 
If x1,x2,x3,x4 are the roots of the equation x4-x3


sin2(Beta)+x2 cos 2(Beta)-x cos(Beta)-sin(Beta)=0 then
summation i=1 to 4 of tan^-1 xi is ?
What are the real roots of:

x4-= x * (x3 - 1) = x * (x - 1)(x2 + x + 1)

Continue....
 
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...the equation x4-x3


sin2(Beta)+x2 cos 2(Beta)-x cos(Beta)-sin(Beta)=0...
Are the two lines above actually supposed to be one? In particular, is "the equation" supposed to be as follows?

. . . . .x4 - x3 sin2(Beta) + x2 cos 2(Beta) - x cos(Beta) - sin(Beta) = 0

When you reply, please include a clear listing of your thoughts and efforts so far, so we can see where you're needing assistance. Thank you! ;)
 
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