simplification of Trignometric expression: sinx+sin(x+y)+ - - +sin(x+(n-1)y)=

[Naresh]

As we know
sinx+sin(x+y)+ - - +sin(x+(n-1)y)=sin(ny/2).(sin(x+(n-1)(y/2))/siny/2 then please tell
tanx+tan(x+y)+ - - -+tan(x+(n-1)y) is equal to

 

[Deleted member 4993]

As we know
sinx+sin(x+y)+ - - +sin(x+(n-1)y)=sin(ny/2).(sin(x+(n-1)(y/2))/siny/2 then please tell
tanx+tan(x+y)+ - - -+tan(x+(n-1)y) is equal to

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