A 10by10 square contains 100 1by1 squares (of course!).
A circle is drawn inside above square, tangent to all 4 sides.
How many of the 1by1 squares are fully inside the circle?
Was fiddling with above. I get 60 as answer.
I got just over 19pi as my answer.:smile:A 10by10 square contains 100 1by1 squares (of course!).
A circle is drawn inside above square, tangent to all 4 sides.
How many of the 1by1 squares are fully inside the circle?
Was fiddling with above. I get 60 as answer.
So?I got just over 19pi as my answer.:smile:
You told him to be no square, so he's being obtuse, instead.
I just got over your answer.I got just over 19pi as my answer.
A 10by10 square contains 100 1by1 squares (of course!).
A circle is drawn inside above square, tangent to all 4 sides.
How many of the 1by1 squares are fully inside the circle?
Was fiddling with above. I get 60 as answer.
I disagree. To me, "fully inside the circle" means you can "move freely about inside the circle without being blocked by any part of a square."
That's equivalent to what I said, isn't it?One might ask instead "How many 1 by 1 squares don't have any of their areas outside of the circle?"
I have been away since midnight (this location), and that is why I have not replied sooner. That's just it, if each square is "fullyI don't see how you can interpret it like that; he said each square is fully inside the circle (that is, completely contained within it), and said nothing about someone moving around them, inside the circle. I also don't understand what you think is being asked for. What would your solution be?
Of course, if the wording is interpreted differently, then you are just solving a different problem; the difference is not about the math. But can you explain your interpretation of the English?
That's just it, if each square is "fully inside the circle," then none of the squares that are to count may touch the circle, otherwise those squares are not fully inside the circle. Fully inside the circle squares do not intersect with the circle. If any part of a square is coincident with the circumference of that circle, then that square fails to be fully inside the circle.
The alternative stated question I gave (that Denis requoted) is the intended problem, but I have explained the issue/difference with what was originally asked with a suggestion of a different phrase with a different meaning of what was actually intended by the proposer.
Thanks Lookagain.That's just it, if each square is "fully inside the circle," then none of the squares
that are to count may touch the circle, otherwise those squares are not
fully inside the circle.
Fully inside the circle squares do not intersect with the circle.
If any part of a square is coincident with the circumference of that circle,
then that square fails to be fully inside the circle.
Ah Denis forgot his real analysis somewhat. Nope, a point can lie on the boundary. If I recall correctly, a point is said to be an interior point if you find a neighborhood around that point that lies entirely within the set. A boundary point does not satisfy that condition. I finally got Denis!Thanks Lookagain.
But isn't it a fact that "lines" and "points" have no "size" in geometry?
If so, then a point on the circumference would be "inside"....I think...
If not, then I should have stated:
".....including those with a corner on the circumference" or words to that effect...
On the other hand, your version, "How many 1 by 1 squares don't have any of their areas outside of the circle?", is at least as faulty,
if you're looking for < < precise terms > > -- an "area" is a measurement, not a set of points!
How about, "How many 1 by 1 squares do not extend outside of the circle?" . . . . : ) : )
Thank you.