The area of triangel, given that c = | AB | = 3 and that tanβ =

anomi15

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Hello i need help with following question:

Triangeln △ ABC is right angled at right angle at corner C and angle β at corner B. Calculate triangle area, given that c = | AB | = 3 and that tanβ =

i really do not know how to solve this kind of problems hope someone help me.
 
Hello i need help with following question:

Triangeln △ ABC is right angled at right angle at corner C and angle β at corner B. Calculate triangle area, given that c = | AB | = 3 and that tanβ =

i really do not know how to solve this kind of problems hope someone help me.
What is the expression for area of a triangle in terms of base and height?
 
What kind do you know?

I have thought the following. We say that tan b = 3/11 and the sides adjacent to each other opposite the cat to the angle beta adjacent BC and the standing cat AC. I got late to tan b = 3/11 = b / a and then we also set phytagoras rate so that we for equation systems that look like that. c ^ 2 = b ^ 2 + a ^ 2 3/11 = b / a. Then I do not know how to proceed
 
Hello i need help with following question:

Triangeln △ ABC is right angled at right angle at corner C and angle β at corner B. Calculate triangle area, given that c = | AB | = 3 and that tanβ =

i really do not know how to solve this kind of problems hope someone help me.

This is not a problem you solve directly with a familiar formula; you have to think. We're not here to do the thinking for you, but to help you use whatever you know to figure it out. Unfortunately, we don't yet know where we can start.

In fact, we don't know the whole problem, as you didn't say what tanβ is!

Now, given the tangent, you can find what the sine and cosine are, and use those to find the base and height (that is, sides a and b), and then put those in the standard area formula. So that's probably what I'd do.
 
This is not a problem you solve directly with a familiar formula; you have to think. We're not here to do the thinking for you, but to help you use whatever you know to figure it out. Unfortunately, we don't yet know where we can start.

In fact, we don't know the whole problem, as you didn't say what tanβ is!

Now, given the tangent, you can find what the sine and cosine are, and use those to find the base and height (that is, sides a and b), and then put those in the standard area formula. So that's probably what I'd do.
tanβ=3/11
 
I have thought the following. We say that tan b = 3/11 and the sides adjacent to each other opposite the cat to the angle beta adjacent BC and the standing cat AC. I got late to tan b = 3/11 = b / a and then we also set phytagoras rate so that we for equation systems that look like that. c ^ 2 = b ^ 2 + a ^ 2 3/11 = b / a. Then I do not know how to proceed

the height of triangel is 3 and the width is 11 this is what i think because tan V = 3/11

If the height (b) were 3 and the base (a) were 11, then c could not be 3. But one thing you could do would be to suppose that b = 3x and a = 11x, and solve for x given that a^2 + b^2 = 9.

Or, you could use the suggestion I gave (after you replied, while the replies were still in moderation) to find the sine and cosine using identities or other means, and then use those to find a and b.
 
… △ABC is right angled … at corner C and angle β at corner B.

Calculate triangle area, given that c = AB = 3 and that tanβ = … 3/11
Something is wrong with the given information.

If the triangle's height is 3, then c cannot equal 3 because AB is the longest side.

Otherwise, if c does equal 3, then tan(β) cannot equal 3/11.

Please check your typing. :cool:
 
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