combined worth of two items

eddy2017 said:
I see now. This is the the other equation that I need it. The mistake was in matching the number with the right variable.
r(35)+d24=9433
Click to expand...
I'll go ahead and perform the operation.
I will set the other equation as Jomo set it up just matching the right values.
35r+24d=9433
 
Last edited:
eddy2017 said:
I see now. This is the the other equation that I need it. The mistake was in matching the number with the right variable.
r(35)+d24=9433
Click to expand...
It is correct in spirit. If you want to be technically correct, you should write it as:

r * (35) + d * (24) = 9433

That representation avoids many confusion.
 
`r * (35) + d * (24) = 9433
r + d = 300

1 ((r * (35) + d * (24) = 9433))
-24(( r + d = 300))

35r + 24d = 9433
-24r + -24d=300
Simplyfing
11r = 300 dividing 11 into both sides.
r= 203

Let's solve for d
Using one of the original equations I will plug the value of r and solve for d

r * (35) + d * (24) = 9433
203(35)+ d(24)=9433
7105 + 24d = 9433 subtracting 7105 from both
24d=2328
d=97
Checking
r = 203
d = 97
r + d = 300
203 + 97
= 300
The amount of dolls in stock is 97 when the combined worth of robots and dolls is 9433.
 
eddy2017 said:
`r * (35) + d * (24) = 9433
r + d = 300

1 ((r * (35) + d * (24) = 9433))
-24(( r + d = 300))

35r + 24d = 9433
-24r + -24d=300
Simplyfing
11r = 300 dividing 11 into both sides.
r= 203

Let's solve for d
Using one of the original equations I will plug the value of r and solve for d

r * (35) + d * (24) = 9433
203(35)+ d(24)=9433
7105 + 24d = 9433 subtracting 7105 from both
24d=2328
d=97
Checking
r = 203
d = 97
r + d = 300
203 + 97
= 300
The amount of dolls in stock is 97 when the combined worth of robots and dolls is 9433.
Click to expand...
Incorrect!

You write:

1 ((r * (35) + d * (24) = 9433))
-24(( r + d = 300))

35r + 24d = 9433
-24r + -24d=300 .........................................incorrect ...... it should be -24 * r - 24 * d = -24 * 300

so we get .... what?
 
Subhotosh Khan said:
Incorrect!

You write:

1 ((r * (35) + d * (24) = 9433))
-24(( r + d = 300))

35r + 24d = 9433
-24r + -24d=300 .........................................incorrect ...... it should be -24 * r - 24 * d = -24 * 300

so we get .... what?
Click to expand...
35r + 24d = 9433
-24r - 24d = -24*300
-24r -24d =9433 -7200
Simplifying
11r = 2233. Isolating r
r=203
 
eddy2017 said:
35r + 24d = 9433
-24r - 24d = -24*300
Click to expand...
-24r -24d =9433 -7200 .................................... INCORRECT ................... It should be

35r - 24r =9433 -7200

Simplifying

11r = 2233. ......................................Isolating r ................CORRECT

r=203..................................................CORRECT

What was your FIND?
 
Subhotosh Khan said:
-24r -24d =9433 -7200 .................................... INCORRECT ................... It should be

35r - 24r =9433 -7200

Simplifying
11r = 2233. ......................................Isolating r ................CORRECT
r=203..................................................CORRECT
Click to expand...
Wowwwww, thanks to you all!!!!!!!!!.
 
How are you getting the correct answers with all the mistakes you are making.

Your check is very weak. There are many many values for r and d that add up to 300. In fact there ALL the points on the line r + d = 300.
For example, 0 + 300 = 300, 1 + 299 = 300, 2 + 298 = 300, 9.97 + 290.03, 17sqrt(2) + (300 - sqrt(2)), ....
You also have to check that 35r + 24d = 9433. There are actually an infinite number of solutions to this equation as well. However there is only one value for r and d that satisfies both equations (restriction).
 
Jomo said:
How are you getting the correct answers with all the mistakes you are making.

Your check is very weak. There are many many values for r and d that add up to 300. In fact there ALL the points on the line r + d = 300.
For example, 0 + 300 = 300, 1 + 299 = 300, 2 + 298 = 300, 9.97 + 290.03, 17sqrt(2) + (300 - sqrt(2)), ....
You also have to check that 35r + 24d = 9433. There are actually an infinite number of solutions to this equation as well. However there is only one value for r and d that satisfies both equations (restriction).
Click to expand...
How to find that value?.
 
It would be interesting to know even when the problem does not require it. Or does it?.
 
eddy2017 said:
It would be interesting to know even when the problem does not require it. Or does it?.
Click to expand...
If you mean if a solution requires a check then my response is to always check your answer.
As a student when I left an algebra exam I knew basically what my grade would end up being because I checked my work. When it checked out I know that I earned all the points on that problem. When it did not check out and I could not find my error I knew that I would lose some points
 
Also, we don't need to report any value for r.

\(\;\)
 
Jomo said:
If you mean if a solution requires a check then my response is to always check your answer.
As a student when I left an algebra exam I knew basically what my grade would end up being because I checked my work. When it checked out I know that I earned all the points on that problem. When it did not check out and I could not find my error I knew that I would lose some points
Click to expand...
It is true that I didn't check the first equation.
 
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