Find"x"

B

Berthin Alexander

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Jun 16, 2020
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Find "x". If AC=BC.
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I tried to find congruence. I do not know what more to do. Could you give me ideas please?
intente esto.PNG
 
Dr.Peterson said:
Can you explain the thinking behind your markings, including what the green line is? Some (or maybe all) of them are wrong (such as the two apparently equal angles into which you divided 4x, unequally).
Click to expand...
the green line is a bisector.
Draw the line of that green bisector trying to find congruence of triangles.
I'm honestly not sure how to solve that problem so I posted it on this page
 
Berthin Alexander said:
the green line is a bisector.
Draw the line of that green bisector trying to find congruence of triangles.
I'm honestly not sure how to solve that problem so I posted it on this page
Click to expand...
Use what you do know. You knew to make an angle bisector, which is also the perpendicular bisector of AB. So the two angles on either side of that are both 2x, right?

Go on from there. Use the perpendicularity. No side lengths are needed!
 
pka said:
m(∠CAB)=m(∠CBA)
Click to expand...
Yes, you just need to look at the big triangle ABC. As has been said, [MATH]\bigtriangleup[/MATH] ABC is isosceles,
so you know (in terms of x) the three angles in [MATH]\bigtriangleup[/MATH] ABC: 4x, 3x, ?
and you know what the three angles in a triangle add up to.
 
pka said:
Because \(AC=BC\) is it true that \(\Delta ACB\) is isosceles ?
If so, does that mean that \(m(\angle CAB)=m(\angle CBA)~?\)
What can you now conclude about \(3x+4x+2x+?=\Large ?\)
Click to expand...
I want to apologize to all of you. Mispublish the geometry problem. It is actually AC = BE.
but I already solved it on my own. Anyway, thank you very much for your help and your time. you are good people
 
lex said:
Yes, you just need to look at the big triangle ABC. As has been said, [MATH]\bigtriangleup[/MATH] ABC is isosceles,
so you know (in terms of x) the three angles in [MATH]\bigtriangleup[/MATH] ABC: 4x, 3x, ?
and you know what the three angles in a triangle add up to.
Click to expand...
I want to apologize to all of you. Mispublish the geometry problem. It is actually AC = BE.
but I already solved it on my own. Anyway, thank you very much for your help and your time. you are good people
Harry_the_cat said:
I think you are making this a lot harder than it is. If AC=BC, then triangle ABC is isosceles. Which 2 angles are congruent?
Click to expand...
I want to apologize to all of you. Mispublish the geometry problem. It is actually AC = BE.
but I already solved it on my own. Anyway, thank you very much for your help and your time. you are good people
 
@Berthin Alexander
Berthin Alexander said:
I want to apologize to all of you. Mispublish the geometry problem. It is actually AC = BE.
but I already solved it on my own. Anyway, thank you very much for your help and your time. you are good people
Click to expand...
It gives the same answer - and AC=BC too.
It would be interesting to see your solution.
 
lex said:
@Berthin Alexander

It gives the same answer - and AC=BC too.
It would be interesting to see your solution.
Click to expand...
fdsgdfg4t435.PNG
The ceviana BF is drawn with the idea of forming the angle CFB = 3x. It is concluded that the side BF = AB and that the angle CBF is x. We realize that there is congruence of triangles between AEB and FCB
 
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