Trigonometry: P,A,B,C points in plane s.t. <BPA, <CPA are obtuse and on opposite sides of PA

S

Stardust1

New member
Joined
Jun 14, 2023
Messages
16
Hi, I was wondering how to solve this question. This is not straightforward and I am confused. The question is attached below
1716890655295.png
 
Last edited:
Start with a sketch. Triangle ABC with point P inside of it. You can use law of cosines to find angle APB and angle APC, which would then lead to angle BPC. Now it's law of cosines to find BC. From there, you could use Hero's formula to find the area of the triangle.
 
Can you please elaborate for me? I've tried but I am getting nowhere close to the answer given.
 
Stardust1 said:
Can you please elaborate for me? I've tried but I am getting nowhere close to the answer given.
Click to expand...
Please SHOW what you tried, so we can see how far you really are from a reasonable solution:

Posting Guidelines (Summary)

Welcome to our tutoring boards! :) This page summarizes main points from our posting guidelines. As our name implies, we provide math help (primarily to students with homework). We do not generally post immediate answers or step-by-step solutions. We don't do your homework. We prefer to help...
www.freemathhelp.com

At the very least, show us your sketch.
 
Did draw an approximate sketch?

If you did, please share a picture of the sketch - along with any mathematical work that you have done regarding this problem. Also let us know if you did not understand any "term" that you did not understand in responses 2 & 3.
 
Hi, I worked it out. It seems like I used the wrong formula and didn't do a step properly. Sorry about that.
 
You must log in or register to reply here.
Top