Alg2 quiz this friday help porfavor

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hollerback1

Junior Member
Joined
Dec 21, 2005
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Hola amigos,
How do i find the quadratic model that has given point as a vertex? Assuming that "a" is 1.

1.(3,7)
2.(-1,4) PLEASE HELP ME ASAP
3.(-5,-3)
4.(0,0)

How do you convert those into a quadratic model? Thanks. :wink:
 
A vertical parabola with vertex (h, k) can have its equation written as

\(\displaystyle \mbox{ y = a(x - h)^2 + k}\)

where your a is from \(\displaystyle \mbox{y = ax^2 + bx + c}\).

Feel like some algebra practise? Complete the square on \(\displaystyle \mbox{ y = ax^2 + bx + c}\), then let \(\displaystyle \mbox{h = -\frac{b}{2a}}\) and \(\displaystyle \mbox{k = c - \frac{b^2}{4a}}\) to derive it.
 
Thankyoo for responding :lol: but please answer one of the questions I have gaven you as an example. Thanks. Sinceramente Hollerrrrrrr

Like: (2,3)
 
Um...that is not what i wanted. I wanted the quadratic equation for (2,3) thanks.
 
\(\displaystyle \mbox{ y = a(x - h)^2 + k}\)

Substituting (h, k) = (2, 3) and a=1:

\(\displaystyle \mbox{ y = (x - 2)^2 + 3}\)
 
You've been given the relationship between the vertex (h, k) and the parabola's equation, so all you're left with is a simple matter of plugging into the provided formula. Where are you stuck?

Please reply with specifics. Thank you.

Eliz.
 
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