algebra

Linda Willup

New member
Joined
Jan 5, 2006
Messages
2
I think this is right

3c + 6(4c)=1,350

3c=24c=1,350

27c=1,350
27 27

c = 50
Could you let me know?
 
Linda Willup said:
I think this is right

3c + 6(4c)=1,350

3c=24c=1,350

27c=1,350
27 27

c = 50
Could you let me know?

Nicely done! You're right.
 
Linda Willup said:
I think this is right
It looks like you did the following:

. . . . .3c + 6(4c) = 1350

. . . . .3c + 24c = 1350

. . . . .27c = 1350

. . . . .(27c)/27 = (1350)/27

. . . . .c = 50

Linda Willup said:
Could you let me know?
You don't need us for that! :wink:

To check the answer to any "solving" exercise, plug your solution back into the original problem and see if it works:

. . . . .3[50] + 6(4[50]) ?=? 1350

. . . . .150 + 6(200) ?=? 1350

. . . . .150 + 1200 ?=? 1350

. . . . .1350 = 1350

It checks, so your solution is correct.

Eliz.
 
Top