Algebra

vjackson

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Aug 30, 2012
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Simplify sqare root of 288 to the form a(radical)b, where a and b are positive integers and b is square free.
 
Can you factor out squares: Which of "4", "9", "16", "25" etc will divide evenly into 288?
\(\displaystyle \sqrt{a^2b}= a\sqrt{b}\).
 
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