Area of triangle with angle of 5*pi/6

[ElissaHatesMath]

I hope I'm posting this in the right place. I'm in pre-calculus 2.

The question is the isosceles triangle has an angle of 5*pi/6 between the two equal sides. The area is 23cm^2. What is the length of the two equal sides?

I believe the degrees of the angle is 150. This is what I have so far

1) 23cm^2 = 1/2*a*b*sin 150

2)I know sin 150 =1/2 so I combine like terms:

23cm^2=1/4*ab

I get lost from there. I'm not even sure what I have done is right so far since the professor didn't really cover this type of problem.

 

[tkhunny]

I hope I'm posting this in the right place. I'm in pre-calculus 2.

The question is the isosceles triangle has an angle of 5*pi/6 between the two equal sides. The area is 23cm^2. What is the length of the two equal sides?

I believe the degrees of the angle is 150. This is what I have so far

1) 23cm^2 = 1/2*a*b*sin 150

2)I know sin 150 =1/2 so I combine like terms:

23cm^2=1/4*ab

I get lost from there. I'm not even sure what I have done is right so far since the professor didn't really cover this type of problem.

Come now, Elissa. Math doesn't hate you.

In this case, you have reasoned it out nicely. You need just one more clue from the problem statement. Are "a" and "b" related?

You got this! No more hating.

 

[ElissaHatesMath]

problem solved

Come now, Elissa. Math doesn't hate you.

In this case, you have reasoned it out nicely. You need just one more clue from the problem statement. Are "a" and "b" related?

You got this! No more hating.

problem solved, thanks

 

[Harry_the_cat]

problem solved, thanks

Well done! Now change your name to ElissaLovesMath!