basic geometry

poltrock

New member
Joined
Mar 3, 2015
Messages
6
The area of a triangle is 100 square inches.The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the second rectangle a square? explain why or why not. that is the question as stated. Also is it possible to have a perimeter of 40 inches and have an area of 100 inches.
 
Last edited by a moderator:
The area of a triangle is 100 square inches.The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the second rectangle a square? explain why or why not. that is the question as stated. Also is it possible to have a perimeter of 40 inches and have an area of 100 inches.

You have mixed types "The area of a triangle is 100 square inches.The perimeter of the rectangle is 40 inches." However, assuming a rectangle in both cases, if p is the perimeter and a is the area then \(\displaystyle a\, \le\, (\frac{p}{4})^2\). Since \(\displaystyle 100\, \le\, (\frac{40}{4})^2 = 100\), yes, a rectangle can have a perimeter of 40 inches and have an area of 100 inches.
 
The area of a triangle is 100 square inches.The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the second rectangle a square? explain why or why not. that is the question as stated. Also is it possible to have a perimeter of 40 inches and have an area of 100 inches.

HINT: If x is one side of a rectangle and y is the other side, what is the formula for the perimeter? What is the formula for the area. Given those two equations, how would you solve for the two variables?
 
sorry the post at 6:49 pm is the correct question the triangle should be rectangle, apologize.
 
the question is as stated in Common core reteaching and practice, Envision math common core, but the question has no other available info.
 
The question is not triangle I must have made a mistake it should be rectangle, very much apologize.
 
The question is not triangle I must have made a mistake it should be rectangle, very much apologize.

Look at the hint above (or below, depending on how you have set your preferences) and show us what you have done.
 
I see the formula as written 40 over 4 squared =100 but, can that happen in 2 dimensional space.
Start over. Given x as width and y as the length of a rectangle what are the formulas for the perimeter and area?

Answer:
perimeter = 2 (x+y)
area = x * y

Now if the area is 100 and the perimeter is 40, what are x and y?
 
it would the answer is 10.
Correct x=y=10, so the rectangle is a square.

Now suppose a second rectangle has the same area (100) but a different perimeter. Since the area is the same, from the formula above, \(\displaystyle a\, \le\, (\frac{p}{4})^2\, or\, 4\, \sqrt{a}\, \le\, p\), we have that the perimeter has to be larger than 40. So let the perimeter be 40 + 2d where d is positive and we have
x + y = 20 + d
x y = 100.
What is x and y? Are they the same? If not, the rectangle is not a square. From this can you give a formula of the perimeter in terms of the area (or area in terms of the perimeter) given that the rectangle is a square?
 
Top