Calculate v_o and I_o in the circuit.
logistic_guy Senior Member Joined Apr 17, 2024 Messages 2,214 Sep 18, 2025 #1 Calculate \(\displaystyle v_o\) and \(\displaystyle I_o\) in the circuit.
K khansaheb Senior Member Joined Apr 6, 2023 Messages 1,223 Sep 18, 2025 #2 logistic_guy said: Calculate \(\displaystyle v_o\) and \(\displaystyle I_o\) in the circuit. View attachment 39754 Click to expand... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: READ BEFORE POSTING Please share your work/thoughts about this problem
logistic_guy said: Calculate \(\displaystyle v_o\) and \(\displaystyle I_o\) in the circuit. View attachment 39754 Click to expand... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: READ BEFORE POSTING Please share your work/thoughts about this problem
logistic_guy Senior Member Joined Apr 17, 2024 Messages 2,214 Sep 19, 2025 #3 Let us try KVL and hope that it will work. From the first loop, we get: \(\displaystyle 0.015 - 4000I_1 - \frac{v_o}{100} = 0\) We also know that \(\displaystyle I_1 = -I_o\) Then, \(\displaystyle 0.015 + 4000I_o - \frac{v_o}{100} = 0\)
Let us try KVL and hope that it will work. From the first loop, we get: \(\displaystyle 0.015 - 4000I_1 - \frac{v_o}{100} = 0\) We also know that \(\displaystyle I_1 = -I_o\) Then, \(\displaystyle 0.015 + 4000I_o - \frac{v_o}{100} = 0\)
logistic_guy Senior Member Joined Apr 17, 2024 Messages 2,214 Sep 21, 2025 #4 Second loop. \(\displaystyle v_o = 20000I_2 = 20000(50I_o) = 1000000I_o\)
logistic_guy Senior Member Joined Apr 17, 2024 Messages 2,214 Sep 24, 2025 #5 \(\displaystyle 0.015 + 4000I_o - \frac{v_o}{100} = 0\) \(\displaystyle 0.015 + 4000I_o - \frac{1000000I_o}{100} = 0\) \(\displaystyle 0.015 + 4000I_o - 10000I_o = 0\) \(\displaystyle 0.015 - 6000I_o = 0\) \(\displaystyle 6000I_o = 0.015\) \(\displaystyle I_o = \frac{0.015}{6000} = 2.5 \times 10^{-6} \ \text{A} = \textcolor{blue}{2.5 \ \mu \text{A}}\)
\(\displaystyle 0.015 + 4000I_o - \frac{v_o}{100} = 0\) \(\displaystyle 0.015 + 4000I_o - \frac{1000000I_o}{100} = 0\) \(\displaystyle 0.015 + 4000I_o - 10000I_o = 0\) \(\displaystyle 0.015 - 6000I_o = 0\) \(\displaystyle 6000I_o = 0.015\) \(\displaystyle I_o = \frac{0.015}{6000} = 2.5 \times 10^{-6} \ \text{A} = \textcolor{blue}{2.5 \ \mu \text{A}}\)
logistic_guy Senior Member Joined Apr 17, 2024 Messages 2,214 Sep 26, 2025 #6 We continue like heroes. \(\displaystyle v_o = 1000000I_o = 1000000(2.5)(10^{-6}) = \textcolor{blue}{2.5 \ \text{V}}\)
We continue like heroes. \(\displaystyle v_o = 1000000I_o = 1000000(2.5)(10^{-6}) = \textcolor{blue}{2.5 \ \text{V}}\)