The road from A to B is 10km uphill followed by 20km downhill. a motorcyclist averages 36km/hr uphill and 90km/hr downhill. Calculate the average speed (a) from A to B (b) from B to A?
At least I can solve the first part of the questions.
[math]\text{Time uphill} =\frac{10}{36}~\text{hrs}[/math][math]\text{Time downhill} =\frac{20}{90}~\text{hrs}[/math][math]\text{Total time} =\frac{5}{18}+\frac{2}{9}=\frac{1}{2} ~\text{hrs}[/math][math]\text{Total distance} = 30 km[/math][math]\text{Avg speed} = \frac{30}{\frac{1}{2}} = 60~ km/hr[/math]I can solve the second part of the problem if I can the picture of the problem correctly. Is this the correct picture of the problem?
At least I can solve the first part of the questions.
[math]\text{Time uphill} =\frac{10}{36}~\text{hrs}[/math][math]\text{Time downhill} =\frac{20}{90}~\text{hrs}[/math][math]\text{Total time} =\frac{5}{18}+\frac{2}{9}=\frac{1}{2} ~\text{hrs}[/math][math]\text{Total distance} = 30 km[/math][math]\text{Avg speed} = \frac{30}{\frac{1}{2}} = 60~ km/hr[/math]I can solve the second part of the problem if I can the picture of the problem correctly. Is this the correct picture of the problem?
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