calculus1 integral

For part b): if each of [imath]\alpha(x)~\&~\beta(x)[/imath] is a differentiable function then if
[imath]\displaystyle G(x) = \int_{\beta (x)}^{\alpha (x)} {\Phi (t)dt}[/imath] we get [imath]G^{\prime}(x)=\alpha^{\prime}(x)\Phi(\alpha(x))-\beta^{\prime}(x)\Phi(\beta(x))[/imath]
 
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