Here is one way to tackle it.
Designate your first odd as 2x+1. The second odd would then be 2x+3, the third would be 2x+5.
The product of the first and third: (2x+1)(2x+5)
Is 6 more than 3 times the second 3(2x+3)+6
Equate them and solve for x. Then, sub it into 2x+1 to see what the first one is.
Since they are consecutive, it is easy to see what the other two will be.
Check to see if they meet the requirements.