kaknutson2
New member
- Joined
- Nov 12, 2010
- Messages
- 4
Let AB be a diameter of a circle, and let UV be a chord perpendicular to AB. Show that cr(A, U, B, V) = 2
So far I've tried using the cross ration theorem (suppose that A, U, B, V are distinct collinear points in perspective from some point P with distinct collinear points W, X, Y, and Z respectively. Then cr(A, U, B, V)=cr(W, X, Y, Z)) but that is as far as I've gotten. If I can find another cross ration that cr(A, U, B, V) is equal to I think I can prove it equals two, but I can't find one, or maybe am not drawing it correctly. Please help!
So far I've tried using the cross ration theorem (suppose that A, U, B, V are distinct collinear points in perspective from some point P with distinct collinear points W, X, Y, and Z respectively. Then cr(A, U, B, V)=cr(W, X, Y, Z)) but that is as far as I've gotten. If I can find another cross ration that cr(A, U, B, V) is equal to I think I can prove it equals two, but I can't find one, or maybe am not drawing it correctly. Please help!
