The terminal arm of angle ? in standard position passes through point (m, n) where m > 0, n > 0. Determine the value of
sin(pi + ?).
My work.
? is originally in quadrant 1. Add pi to it, so it would be in the third quadrant. The reference angle has not changed.
Draw a right triangle the on Cartesian plane in the third quadrant. -m is on the negative part of the x-axis. -N is on the negative part of the y-axis
Hypotenuse^2 = (-m)^2 + (-n)^2
Hypotenuse = ± sqrt(m^2+n^2)
So the answer is either -n/[-sqrt(m^2+n^2)] = n/[sqrt(m^2+n^2) ] or -n/[sqrt(m^2+n^2)]
I'm thinking it's -n/[sqrt(m^2+n^2)] because the hypotenuse cannot be negative. Is my thinking correct?
sin(pi + ?).
My work.
? is originally in quadrant 1. Add pi to it, so it would be in the third quadrant. The reference angle has not changed.
Draw a right triangle the on Cartesian plane in the third quadrant. -m is on the negative part of the x-axis. -N is on the negative part of the y-axis
Hypotenuse^2 = (-m)^2 + (-n)^2
Hypotenuse = ± sqrt(m^2+n^2)
So the answer is either -n/[-sqrt(m^2+n^2)] = n/[sqrt(m^2+n^2) ] or -n/[sqrt(m^2+n^2)]
I'm thinking it's -n/[sqrt(m^2+n^2)] because the hypotenuse cannot be negative. Is my thinking correct?