diferencial equation prob: y'+tg(x)=sec(x), sen(x)y'+cos(x)y=xsen(x)

flaviogaucho

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Jun 29, 2015
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need help with this two diferencial equation, someone can help me?

y'+tg(x)=sec(x)

and

sen(x)y'+cos(x)y=xsen(x)
 
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1. y'+tg(x)=sec(x)

2. sen(x)y'+cos(x)y=xsen(x)
In (1), does "tg" stand for the "tangent" function (illustrated here])? In (2), does "sen" stand for the "sine" function (illustrated here])?

When you reply, please include a clear listing of your efforts so far. Thank you! ;)
 
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