(t^2+8t-15)/(t+4)
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Aug 26, 2010 #2 tina4545 said: (t^2+8t-15)/(t+4) Click to expand... Your attempt is invisible.
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Aug 26, 2010 #3 \(\displaystyle \frac{t^2+8t-15}{t+4} \ = \ t+4-\frac{31}{t+4}\) \(\displaystyle Check: \ (t+4)\bigg(t+4-\frac{31}{t+4}\bigg) \ = \ t^2+8t-15\)
\(\displaystyle \frac{t^2+8t-15}{t+4} \ = \ t+4-\frac{31}{t+4}\) \(\displaystyle Check: \ (t+4)\bigg(t+4-\frac{31}{t+4}\bigg) \ = \ t^2+8t-15\)
