Double Integrals

CatchThis2

Junior Member
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Feb 6, 2010
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I keep getting 480 for an answer which is incorrect. Does anyone know where I am going wrong.

Find iint_R f(x,y) dA where f(x,y) = 2 x + 2 and R = [0, 2] times [3, 6].
iint_R f(x,y)dA =
 
CatchThis2 said:
I keep getting 480 for an answer which is incorrect. Does anyone know where I am going wrong.

Find iint_R f(x,y) dA where f(x,y) = 2 x + 2 and R = [0, 2] times [3, 6].
iint_R f(x,y)dA =

For that to happen - we need to see what you have done.
 
iint_R(x=0 to 3)(y=2 to 6) (2x+2)*dx*dy
AS it is a function of only x any variable can be integ first. Let us start with y
integ (x=0 to 3) (2x+2)*y(from 6 to 2)
integ (x=0 to 3) 4*(2x+2)*dx
4*(x^2+2x)(for x=0 to 3)
I think you can carry on from here. Answer must be 60.
 
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