electric circuit

From the first loop, we get:

\(\displaystyle 10 - 16I - 14I - 25 = 0\)

This gives:

\(\displaystyle I = -0.5 \ \text{A}\)
 
From the first loop, we get:

\(\displaystyle 10 - 16I - 14I - 25 = 0\)

This gives:

\(\displaystyle I = -0.5 \ \text{A}\)
To make sense of the calculation shown above, the assumed direction of the loop current MUST be shown.
 
From the second loop, we get:

\(\displaystyle 10 - 16I - V_{o} = 0\)

We already know that \(\displaystyle I = -0.5 \ \text{A}\)

Then,

Determine \(\displaystyle V_{o}\) in the circuit.
\(\displaystyle V_{o} = 10 - 16I = 10 - 16(-0.5) = \textcolor{blue}{18 \ \text{V}}\)
 
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