equation with fractions as exponents: .4k 1/3 = .1k

.4k[1/3]=.1K multiply both sides of the equal sign by 3
.4k=.3k subtract .3k from each side
.1k=0
either .1=0 [impossible] , or k=0 answer

the original equation was probably

.4k+1/3=.1k multiply both sides by 3
1.2k+1=.3k subtract .3k from each side
.9k+1=0 subtract 1 from each side
.9k=1
k=1/.9 answer or multiply numerator and denominator by 10
k=10/9
k=1 1/9 answer or
k=1.111... answer
Arthur
 
.4k^1/3 =.1k divide both sides by .1
4k^1/3 =k cube both sides
64k= k^3 subtract 64k from both sides
0=k^3-64k factor out k
0=k[k^2-64] factor k^2-64
0=k[k-8][k+8]

k=0 or k=8 or k=-8 answer
Arthur
 
Re: equation with fractions as exponents

art2ista said:
solve for k. .4k 1/3 = .1k
Click to expand...
Did you mean "0.4k^(1/3) = 0.1k", as was discussed here? Or something else?

Thank you.

eliz.
 
.4k^1/3 =.1k divide both sides by .1
4k^1/3 =k cube both sides
64k= k^3 subtract 64k from both sides
0=k^3-64k factor out k
0=k[k^2-64] factor k^2-64
0=k[k-8][k+8]

k=0 or k=8 or k=-8 answer
Arthur

Arthur, i don't understand how you got rid off k^1/3. can you please help me?
 
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