Exponential problem

[Guest]

If N = 1000e^-kt and N = 200 when t =2, then an exact value for k is

a) 1/2 loge2
b)-1/2 loge2

I would say a but there is not such an answer in the multiple choices.


thanks in advance...

 

[stapel]

If N = 1000e^-kt and N = 200 when t =2, then an exact value for k is...

Plug "200" in for "N" and "2" in for "t". Solve for "k". A good first step would be to divide through by 1000. Then take the natural log of each side of the equation.

a) 1/2 loge2
b)-1/2 loge2

I would say a but there is not such an answer in the multiple choices.

Um... it looks to me like there is an option "a" in the listing you quoted...?

Eliz.