(5y)2 /52y and (b2)8/(b5)3 Please help:confused:
M Moki New member Joined Aug 23, 2012 Messages 1 Aug 23, 2012 #1 (5y)2 /52y and (b2)8/(b5)3 Please help
H HallsofIvy Elite Member Joined Jan 27, 2012 Messages 7,763 Aug 25, 2012 #2 Are you asked to simplify those expressions? If so you need to know the 'laws of exponents' (which, I bet, are in your text): \(\displaystyle a^xa^y= a^{x+y}\) \(\displaystyle \frac{a^x}{a^y}= a^{x- y}\) and \(\displaystyle (a^x)^y= a^{xy}\) Last edited by a moderator: Aug 25, 2012
Are you asked to simplify those expressions? If so you need to know the 'laws of exponents' (which, I bet, are in your text): \(\displaystyle a^xa^y= a^{x+y}\) \(\displaystyle \frac{a^x}{a^y}= a^{x- y}\) and \(\displaystyle (a^x)^y= a^{xy}\)
D Deleted member 4993 Guest Aug 25, 2012 #3 Moki said: (5y)2 /52y and (b2)8/(b5)3 Please help Click to expand... Problem #1 If the expression is: \(\displaystyle \dfrac{(5y)^2}{5^2y}\) it should be written as → (5y)2/(52y) As written: (5y)2 /52y means → \(\displaystyle \dfrac{(5y)^2}{5^2}y\) Those parentheses in the denominators are super important. Those can change the result If you do not post correct and complete problem - we cannot help you effectively. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
Moki said: (5y)2 /52y and (b2)8/(b5)3 Please help Click to expand... Problem #1 If the expression is: \(\displaystyle \dfrac{(5y)^2}{5^2y}\) it should be written as → (5y)2/(52y) As written: (5y)2 /52y means → \(\displaystyle \dfrac{(5y)^2}{5^2}y\) Those parentheses in the denominators are super important. Those can change the result If you do not post correct and complete problem - we cannot help you effectively. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.