kelseysane18
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- Jun 30, 2013
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The range of a projectile that is launched with an initial velocity v at an angle of theta with the horizon is given by R=v2/g sin2theta, where g is the acceleration due to gravity or 9.8 m/2.
1. if a projectile is launched with an initial velocity of 25 m/s what angle is required to reach a range of 30 meters?
1. if a projectile is launched with an initial velocity of 25 m/s what angle is required to reach a range of 30 meters?