Find determinant of matrix of second partials (regularities of product life cycle)

ShubhamRathi

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Aug 28, 2016
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Consider the Equations.:
g'(rd*)G = 1 ... (3)
[ Q it-1 (Qt/ Q t-1) + Δ qit* ] l (rcit*)=1 ... (4)
Its then said, Differentiating (3)-(4) with respect to Qit - 1 and rearranging yields:
d rc*/d Q it-1 = g’’ (rdit) G m’’ (Δ qit) l’ (rcit*) x (Qt/ Q t-1) /D ... (5)
d Δ qit* / d Q t-1 = g’’ (rdit) G l’ (rcit )2 x (Qt/ Q t-1) /D ... (6)
where D is the determinant of the matrix of second partials.
** What is D. How does one calculate it? Can someone please explain the calculus that is happening here?**
Just if someone wants to get in more details, the paper is here. This result is Lemma 2 on page 10/23.


 
Consider the Equations.:
g'(rd*)G = 1 ... (3)
[ Q it-1 (Qt/ Q t-1) + Δ qit* ] l (rcit*)=1 ... (4)
Its then said, Differentiating (3)-(4) with respect to Qit - 1 and rearranging yields:
d rc*/d Q it-1 = g’’ (rdit) G m’’ (Δ qit) l’ (rcit*) x (Qt/ Q t-1) /D ... (5)
d Δ qit* / d Q t-1 = g’’ (rdit) G l’ (rcit )2 x (Qt/ Q t-1) /D ... (6)
where D is the determinant of the matrix of second partials.
** What is D. How does one calculate it? Can someone please explain the calculus that is happening here?**
Just if someone wants to get in more details, the paper is here. This result is Lemma 2 on page 10/23.
There is no "D" in Lemma 2 (on page 9 of 23). Do you maybe mean Lemma 3? If so, then D is defined as:

D is the determinant of the matrix of second partials of \(\displaystyle \,E\left(\Pi_{it}\right)\,\) with respect to rdit, rcit, and \(\displaystyle \,\Delta q_{it},\,\) evaluated at \(\displaystyle \,rd_{it}^{*},\, rc_{it}^{*},\, \) and \(\displaystyle \,\Delta q_{it}^{*}.\)
 
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