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Find dy/dx for y^2+e^y-3x^2+xy=2pai.
- Thread starter czllh5
- Start date
HallsofIvy
Elite Member
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- Jan 27, 2012
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- 7,763
I assume that your "pai" is what I would call "pi": \(\displaystyle \pi\).
Now, what is your difficulty? Do you know the derivative of \(\displaystyle x^n\)? What about the derivative of \(\displaystyle e^x\)? Do you know the chain rule? Do you know that the derivative of f+ g is the derivative of f plus the derivative of g?
I think that about covers what you need to use!
Now, what is your difficulty? Do you know the derivative of \(\displaystyle x^n\)? What about the derivative of \(\displaystyle e^x\)? Do you know the chain rule? Do you know that the derivative of f+ g is the derivative of f plus the derivative of g?
I think that about covers what you need to use!
I assume that your "pai" is what I would call "pi": \(\displaystyle \pi\).
Now, what is your difficulty? Do you know the derivative of \(\displaystyle x^n\)? What about the derivative of \(\displaystyle e^x\)? Do you know the chain rule? Do you know that the derivative of f+ g is the derivative of f plus the derivative of g?
I think that about covers what you need to use!
But it is e^y, when we differentiate, we get e^dy/dx, then with the other parts, I don't know how to get dy/dx directly.
D
Deleted member 4993
Guest
But it is e^y, when we differentiate, we get e^dy/dx, then with the other parts, I don't know how to get dy/dx directly.
HoI forgot to mention chain rule - which says
\(\displaystyle \dfrac{df(g(x))}{dx} \ = \ \dfrac{df(g(x))}{dg(x)} \ * \dfrac{dg(x)}{dx} \)
so
\(\displaystyle \dfrac{d(e^y)}{dx} \ = \ \dfrac{d(e^y)}{dy} \ * \dfrac{dy}{dx} \ = \ e^y \ * \dfrac{dy}{dx}\)
HallsofIvy
Elite Member
- Joined
- Jan 27, 2012
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- 7,763
HoI forgot to mention chain rule -
I did mention it:
"Now, what is your difficulty? Do you know the derivative of x n ? What about the derivative of e x ? Do you know the chain rule? Do you know that the derivative of f+ g is the derivative of f plus the derivative of g?"
D
Deleted member 4993
Guest
I did mention it:
"Now, what is your difficulty? Do you know the derivative of x n ? What about the derivative of e x ? Do you know the chain rule? Do you know that the derivative of f+ g is the derivative of f plus the derivative of g?"
Ooops - so you did!!
In the early morning haze - before coffee - somehow I glossed over it.