finding magnitude of resultant force, direction of movement

btrfly24

New member
Joined
Jan 7, 2007
Messages
22
Man, I'm having a tuff time tonight?! I attached the picture that I drew of the diagram because it's easier than trying to explain it! Could someone please point me in the right direction? Thanks in advance. Catherine.

untitledus5.png
 
Hello, Catherine!

Do you mean that the diagram looks like this?
Code:
                          * 1
                      *
              200 *
              *
          *  20°
      *   *   *   *   *   * 2
        * 30°     500
          *
            *
              *
            800 *
                  *
                    *
                      * 3

I would write the forces in vector form.

. . \(\displaystyle \begin{array}{ccc}\vec{v_1}\:= & \left\langle-200\cos20^o,\,200\sin20^o\right\rangle \\
\vec{v_2}\:= & \left\langle 500,\,0\right\rangle \\
\vec{v_3}\:= & \left\langle 800\cos(-30^o),\,800\sin(-30^o)\right\rangle \end{array}\)

. . and add them.

 
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