Gives the measure, in degrees, of an angle for which the secant is positive and the cotangent is negative – explain your reasoning

In which quadrant(s) is the secant function positive? In which quadrant(s) is the cotangent function negative? Is there any intersection of these two sets?
 
c_r_a_15 said:
Help me with this trig problem. please and thank you!!!!!
Click to expand...
Because \(\displaystyle \sec(x)=\frac{1}{\cos(x)}\) then cosine & secant have the same sign in any quadrant
Because \(\displaystyle \cot(x)=\frac{1}{\tan(x)}\) then cotangent & tangent have the same sign in any quadrant.
 
You must log in or register to reply here.
Top